[ Pobierz całość w formacie PDF ]
.Q-Q5, then 44 R(6)xN Rx +45 K-B I RxB 46 Q-N5+ K-R I 47 RxR wins.(c) Passive moves like 41.Q-K2 or 41.Q-Q I are refuted by42 Q-B2 and 42 Q-K3.Black then loses either his K pawn orKR pawn, without compensation.(d) The greatest di culties seem to appear a er 41.N-Q2 42RxR KxR, but even then we came to the conclusion thatWhite's attack must prevail a er 43 BxP P-B4 44 Q-K2!(e) We did not analyse Botvinnik's move, but it does not presentWhite with any great di culties.41.Q-BI (3,11) 42 Q-K3 (2,39) N-Q4 (3,11) 43 R xR(2,40) Q (3,11) 44 Q -K5! (2,41) There has been a transitionx Rinto an end-game which sporadically assumes middle gamecharacteristics.The constant problem for the player with the betterposition is how best to realise his advantage technically.White hasthis problem here and it seemed to him that he would not gainenough for his great advantage by transposing into the endgamewith 44 QxP QxQ 45 RxQ R-N5 46 B-B4 K-B2 44." "N-82 (3,12) What would you play now?Game No.40 16793* * *Q-Q ! (2, 49)Excellent! Whilst his opponent has to set up a cramped defence ofhis king's side, the white queen journeys to the opposite flank.43.Q- (3, 15) If 45.P-R3 46 Q-N6 then 46.N-K Idoes not work because of 47 Rx , and a er 46.N-Q4 47Q-Q8+ Q-B1, then the thematic decoy sacrifice 48 BxRP+ !wins.B xP+ ! (2,57) R xB (3,17) 47 Q-N5+ (2,5S) K-Rl (3,IS) If 47.R-N2, then the decoy sacrifice again follows, thistime with the rook, 48 Q-Q8+ Q-B I 49 R-R8+.Q-QS+(2,5S) K-N2 (3, IS) 49 R xR+ (2,59) K xR (3,IS) 50 Q xN+ (2,5S) K-N3 (3, 20) 51 Q xNP (2, 5S) With the aid of a littlecombination, White has won two pawns.There now follows thetechnical realisation of this advantage.51.Q-K5 52 Q-R6! Tocapture a third pawn greedily, by playing 52 QxRP Q-K8+ 53K-N2 Q-K5+ 54 K-R2 Q-B6 55 P-Q5 BPxP would giveBlack a dangerous passed pawn.52.Q-KS+ 53 K-N2Q-K5+ 54 K-Bl Q-NS+ 55 K-K2 Q-B7+ 56 K-BJQ- + 57 K-K3 Q-N4+ 5S K-K2 Q-R4+ 59 K-Q2 K-BJQxBP Q-R4+ 61 Q-BJ QxP+ 62 K-K3 K-B2 63P-Q5! Now ite gets two concealed passed pawns.63.P xP63.P-K5 64 Q-B4 64 Q-B7+ K-BJ 65 Q-B6+ K-K2 66QxP Q-RS 67 Q-K4+ K-B2 6S K-B4 Q-Q + 69 K-N4Q-QRS 70 Q-Q5+ K-Bl 71 K- Q-NS+ 72 K-Resigns.At last! That was a tough struggle!168ANSWERS1 1 3.P x B would allow the typical knight sacrifice 14 N - Q5 ! a erwhich 14.P x N 1 5 P x P dis.ch.opens the K file with mating threats,or 1 4.N-Q2 leads to 1 5 N-N5 B-K4 16 N-B 7+ QxN 1 7B xP+ K-QI I S N-K6 mate.2 If 21.K-Q1 22 B- R5 B-KI Tal had planned 23 Rx P! P xR (ifBlack declines the sacrifice, the rook retreats and Black's wrecked pawnposition spells defeat) 24 N x P+ K-Q2 25 N x R+ K-QI 26 R xP+Bx R 27 N- K6 mate.3 A er 1 1.P - QR3 there could follow 12 B x N B x B 13 N x B Q x B1 4 Q-Q6! (almost a patent of Tal' s! ) N-K2 1 5 KR -QI ! NxN 16Q-Q7+ K-BI 17 Qx NP winning.4 If 1 2.B-K2 in the Fischer-Rubinetti game, after 13 N - B6 Q- B214 Nx B QxN 1 5 P-QN4 N-R5 16 Nx N Px N 1 7 Bx N Px BBlack would have no compensation for the weakened pawn position.5 A er 1 3.N - B4?? White's reply is so simple and crushing that wehope you weren't caught out: 14 B x N P x B 15 N - B6 Q- BI 16N x BP mate!6 A er 1 7.R-BI Tal intended IS P-QN4! N(4) -K5 19 Qx P Nx B20 Q-R4+ ! K-B2 2 1 Q-R7 mate.7 Larsen did not relish 16.P x B because of 17 N-B5! B-B4+ ISK-RI 0-0-0 19 N-Q6+ Bx N 20 Qx B B-B3 (if 20.B-N421 Q - B5 + ) 21 Q - K 7! with unpleasant threats.8 After 20.B-B3 White has 21 N- N3! Q-N5 22 Nx P Q-N4 23Q-K2! when 23.0-0 fails to 24 N xP ! etc.9 White has no forced mate a er 21.,.K - Q2 but wins so muchmaterial that mate would not be long in coming e.g.22 B - KB5 +K-B3 23 B-K4+ N-Q4 24 Bx N+ (or even 24 Rx N!) K-Q2 25B x R+ (the simplest) K-K3 26 P=Q Rx Q 27 Rx R etc.Wouldn'tyou resign rather than face this!10 Accepting the sacrifice is no improvement.The finish could have been1 5 P x N 16 Q-R5 + K-BI (or 16.K-Q2 1 7 Q-N4!) 1 7 P x PB-B3 IS P-K7+! (line clearance) Qx P 19 R-QS + (diversionarysacrifi ) Q x R 20 Q- B7 mate.Also IS R-Q7! would win here.11 The second acceptance would be just as catastrophic: 1 7.P x N ISKR - BI + K-NI 19 Q-R5 R-R2 20 Q-KS + B-BI 21 P x P169Q-K2 22 R x B +! wins.12 If 7.P-Q5 then S N-Q5! N x N 9 P x N P-QR3 (the knightcannot move because of N - B7 double check) 10 N - R3! and Black'sknight is lost to the pin.13 After 1 1.Q-N3 White has 12 P-K5 B-N2 I3 Q-K2! P x P 14Px P N-Q4 1 5 Nx N Bx N 16 Rx B! P x R 1 7 N- Q6+ Bx N ISPx B + K-BI 19 Q-K7+ K-NI 20 Qx N with a winning position.14 If 14.N-B4 1 5 P x P ! N-Q4 ( 1 5.QxP? 16 B-B4) 16 Nx NP x N 1 7 R x P B x R IS Q x B with a c shing attack.15 A er 14.B-B4 Black's queen is too vulnerable on QRS, allowingite to win by 1 5 Nx B Nx N B-N5 +! P x B ( 1 6.K-BI1 7 Q-N4 wins) 1 7 R x Q N-K5 + I S K-K3 N x Q 1 9 R xR etc.16 Tal intended to answer 1 7.Q x N(K5) by IS P x P! giving us twomain lines: ( I ) IS.B-B4+ 19 K-N3 Q-K4+ (1 9 [ Pobierz całość w formacie PDF ]